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The teacher asked the students to read as much as possible of a particular book during the weekend. Balakrishnan read $\frac{1}{2}$ of the book, Angela read $\frac{5}{6}$ of the book, and Subhalakshmi read $\frac{2}{3}$ of the book.

Arrange the three names in the order from the one who read the most to the least. Calculate your reading speed! Reading books is fun and also makes you think about the world!

Please find below the solution to the asked query:

We make denominators of all three fractions same to compare which one is bigger easily , As :

$\frac{1}{2}=\frac{{\displaystyle 1}}{{\displaystyle 2}}\times \frac{3}{3}=\frac{\mathbf{3}}{\mathbf{6}}$

And

$\frac{2}{3}=\frac{2}{3}\times \frac{2}{2}=\frac{\mathbf{4}}{\mathbf{6}}$

Now we can easily say that : $\frac{\mathbf{3}}{\mathbf{6}}\mathbf{}\mathbf{}\mathbf{}\frac{\mathbf{4}}{\mathbf{6}}\mathbf{}\mathbf{}\mathbf{}\frac{\mathbf{5}}{\mathbf{6}}$ , So

We arrange the three names in the order from the one who read the most to the least. As :

**Angela , Subhalakshmi and Balakrishnan ( Ans )**

We know : In weekend we have ' 2 ' days , So

$\mathrm{Reading}\mathrm{speed}\mathrm{of}\mathrm{Angela}=\frac{{\displaystyle \frac{5}{6}}}{2}=\frac{5}{12}\mathrm{book}/\mathrm{day},\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{Reading}\mathrm{speed}\mathrm{of}\mathrm{Subhalakshmi}=\frac{{\displaystyle \frac{2}{3}}}{2}=\frac{1}{3}\mathrm{book}/\mathrm{day}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{And}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{Reading}\mathrm{speed}\mathrm{of}\mathrm{Balakrishnan}=\frac{{\displaystyle \frac{1}{2}}}{2}=\frac{1}{4}\mathrm{book}/\mathrm{day}$

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